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12929434686481 is a prime number
BaseRepresentation
bin1011110000100101111001…
…0111001001010000010001
31200210001010112102012001011
42330021132113021100101
53143313440234431411
643255411133010521
72503056305340355
oct274113627112021
950701115365034
1012929434686481
1141353848a1275
121549989623a41
1372a31839b331
14329b062d5465
151764ce60ac21
hexbc25e5c9411

12929434686481 has 2 divisors, whose sum is σ = 12929434686482. Its totient is φ = 12929434686480.

The previous prime is 12929434686473. The next prime is 12929434686491. The reversal of 12929434686481 is 18468643492921.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11194484705856 + 1734949980625 = 3345816^2 + 1317175^2 .

It is a cyclic number.

It is not a de Polignac number, because 12929434686481 - 23 = 12929434686473 is a prime.

It is a super-2 number, since 2×129294346864812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12929434686461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6464717343240 + 6464717343241.

It is an arithmetic number, because the mean of its divisors is an integer number (6464717343241).

Almost surely, 212929434686481 is an apocalyptic number.

It is an amenable number.

12929434686481 is a deficient number, since it is larger than the sum of its proper divisors (1).

12929434686481 is an equidigital number, since it uses as much as digits as its factorization.

12929434686481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 143327232, while the sum is 67.

The spelling of 12929434686481 in words is "twelve trillion, nine hundred twenty-nine billion, four hundred thirty-four million, six hundred eighty-six thousand, four hundred eighty-one".