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12936669113 = 47275248279
BaseRepresentation
bin11000000110001010…
…11110011110111001
31020101120121212211002
430003011132132321
5202443241402423
65535405414345
7635403605324
oct140305363671
936346555732
1012936669113
115539459a85
12261056a3b5
1312b22298c4
148aa1a17bb
1550aae2228
hex30315e7b9

12936669113 has 4 divisors (see below), whose sum is σ = 13211917440. Its totient is φ = 12661420788.

The previous prime is 12936669103. The next prime is 12936669121. The reversal of 12936669113 is 31196663921.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12936669113 - 218 = 12936406969 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (47), and also a Moran number because the ratio is a prime number: 275248279 = 12936669113 / (1 + 2 + 9 + 3 + 6 + 6 + 6 + 9 + 1 + 1 + 3).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12936669103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 137624093 + ... + 137624186.

It is an arithmetic number, because the mean of its divisors is an integer number (3302979360).

Almost surely, 212936669113 is an apocalyptic number.

It is an amenable number.

12936669113 is a deficient number, since it is larger than the sum of its proper divisors (275248327).

12936669113 is an equidigital number, since it uses as much as digits as its factorization.

12936669113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 275248326.

The product of its digits is 314928, while the sum is 47.

The spelling of 12936669113 in words is "twelve billion, nine hundred thirty-six million, six hundred sixty-nine thousand, one hundred thirteen".

Divisors: 1 47 275248279 12936669113