Base | Representation |
---|---|
bin | 11000000110101001… |
… | …01100110000000001 |
3 | 1020101212010121220002 |
4 | 30003110230300001 |
5 | 203000302102323 |
6 | 5540031125345 |
7 | 635452535612 |
oct | 140324546001 |
9 | 36355117802 |
10 | 12940659713 |
11 | 55407351a3 |
12 | 2611973855 |
13 | 12b2cc60c7 |
14 | 8aa91dc09 |
15 | 50b12e828 |
hex | 30352cc01 |
12940659713 has 2 divisors, whose sum is σ = 12940659714. Its totient is φ = 12940659712.
The previous prime is 12940659661. The next prime is 12940659733. The reversal of 12940659713 is 31795604921.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11115063184 + 1825596529 = 105428^2 + 42727^2 .
It is an emirp because it is prime and its reverse (31795604921) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12940659713 - 224 = 12923882497 is a prime.
It is a super-2 number, since 2×129406597132 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12940659733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6470329856 + 6470329857.
It is an arithmetic number, because the mean of its divisors is an integer number (6470329857).
Almost surely, 212940659713 is an apocalyptic number.
It is an amenable number.
12940659713 is a deficient number, since it is larger than the sum of its proper divisors (1).
12940659713 is an equidigital number, since it uses as much as digits as its factorization.
12940659713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 408240, while the sum is 47.
The spelling of 12940659713 in words is "twelve billion, nine hundred forty million, six hundred fifty-nine thousand, seven hundred thirteen".
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