Base | Representation |
---|---|
bin | 10010110101110110000… |
… | …100010111100001000011 |
3 | 11120210000110200100010122 |
4 | 102311312010113201003 |
5 | 132203140044344413 |
6 | 2430450213050455 |
7 | 162354336342506 |
oct | 22656604274103 |
9 | 4523013610118 |
10 | 1294766012483 |
11 | 45a11a728979 |
12 | 18ab26626a2b |
13 | 951329415c8 |
14 | 4694a3b913d |
15 | 23a2e69e108 |
hex | 12d76117843 |
1294766012483 has 2 divisors, whose sum is σ = 1294766012484. Its totient is φ = 1294766012482.
The previous prime is 1294766012471. The next prime is 1294766012497. The reversal of 1294766012483 is 3842106674921.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1294766012483 - 24 = 1294766012467 is a prime.
It is a super-3 number, since 3×12947660124833 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1294766092483) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 647383006241 + 647383006242.
It is an arithmetic number, because the mean of its divisors is an integer number (647383006242).
Almost surely, 21294766012483 is an apocalyptic number.
1294766012483 is a deficient number, since it is larger than the sum of its proper divisors (1).
1294766012483 is an equidigital number, since it uses as much as digits as its factorization.
1294766012483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3483648, while the sum is 53.
The spelling of 1294766012483 in words is "one trillion, two hundred ninety-four billion, seven hundred sixty-six million, twelve thousand, four hundred eighty-three".
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