Base | Representation |
---|---|
bin | 111100010011110010… |
… | …1110010011110000001 |
3 | 110101022000000002102121 |
4 | 1320213211302132001 |
5 | 4110220342030403 |
6 | 135255250044241 |
7 | 12233313226234 |
oct | 1704745623601 |
9 | 411260002377 |
10 | 129513236353 |
11 | 4aa20933426 |
12 | 21125879681 |
13 | c2a00a53c7 |
14 | 63a899b41b |
15 | 35802623bd |
hex | 1e27972781 |
129513236353 has 4 divisors (see below), whose sum is σ = 129520740400. Its totient is φ = 129505732308.
The previous prime is 129513236327. The next prime is 129513236389. The reversal of 129513236353 is 353632315921.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-129513236353 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (129513236653) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3726075 + ... + 3760672.
It is an arithmetic number, because the mean of its divisors is an integer number (32380185100).
Almost surely, 2129513236353 is an apocalyptic number.
It is an amenable number.
129513236353 is a deficient number, since it is larger than the sum of its proper divisors (7504047).
129513236353 is an equidigital number, since it uses as much as digits as its factorization.
129513236353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7504046.
The product of its digits is 437400, while the sum is 43.
The spelling of 129513236353 in words is "one hundred twenty-nine billion, five hundred thirteen million, two hundred thirty-six thousand, three hundred fifty-three".
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