Base | Representation |
---|---|
bin | 11000001001101001… |
… | …11011001111101011 |
3 | 1020110121121012100112 |
4 | 30010310323033223 |
5 | 203023231304112 |
6 | 5542331524535 |
7 | 636210126503 |
oct | 140464731753 |
9 | 36417535315 |
10 | 12965884907 |
11 | 55539a4268 |
12 | 261a2b974b |
13 | 12b82b8961 |
14 | 8b0008a03 |
15 | 50d463a22 |
hex | 304d3b3eb |
12965884907 has 4 divisors (see below), whose sum is σ = 12966646680. Its totient is φ = 12965123136.
The previous prime is 12965884879. The next prime is 12965884909. The reversal of 12965884907 is 70948856921.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12965884907 - 210 = 12965883883 is a prime.
It is a super-2 number, since 2×129658849072 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12965884909) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 354758 + ... + 389595.
It is an arithmetic number, because the mean of its divisors is an integer number (3241661670).
Almost surely, 212965884907 is an apocalyptic number.
12965884907 is a deficient number, since it is larger than the sum of its proper divisors (761773).
12965884907 is an equidigital number, since it uses as much as digits as its factorization.
12965884907 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 761772.
The product of its (nonzero) digits is 8709120, while the sum is 59.
The spelling of 12965884907 in words is "twelve billion, nine hundred sixty-five million, eight hundred eighty-four thousand, nine hundred seven".
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