Base | Representation |
---|---|
bin | 10010111001100011100… |
… | …011101011111110000001 |
3 | 11121011022011001100201022 |
4 | 102321203203223332001 |
5 | 132234320102013123 |
6 | 2432345424515225 |
7 | 162555150306446 |
oct | 22714343537601 |
9 | 4534264040638 |
10 | 1298750422913 |
11 | 460884834459 |
12 | 18b858a7bb15 |
13 | 95619265208 |
14 | 46c076319cd |
15 | 23bb43951c8 |
hex | 12e638ebf81 |
1298750422913 has 2 divisors, whose sum is σ = 1298750422914. Its totient is φ = 1298750422912.
The previous prime is 1298750422841. The next prime is 1298750422943. The reversal of 1298750422913 is 3192240578921.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 978492899344 + 320257523569 = 989188^2 + 565913^2 .
It is a cyclic number.
It is not a de Polignac number, because 1298750422913 - 210 = 1298750421889 is a prime.
It is a super-2 number, since 2×12987504229132 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1298750422943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 649375211456 + 649375211457.
It is an arithmetic number, because the mean of its divisors is an integer number (649375211457).
Almost surely, 21298750422913 is an apocalyptic number.
It is an amenable number.
1298750422913 is a deficient number, since it is larger than the sum of its proper divisors (1).
1298750422913 is an equidigital number, since it uses as much as digits as its factorization.
1298750422913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2177280, while the sum is 53.
The spelling of 1298750422913 in words is "one trillion, two hundred ninety-eight billion, seven hundred fifty million, four hundred twenty-two thousand, nine hundred thirteen".
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