Base | Representation |
---|---|
bin | 11101100011101111111011… |
… | …110100100001111111010001 |
3 | 122001021212201112000021201002 |
4 | 131203233323310201333101 |
5 | 114014404444444444303 |
6 | 1140253101525551345 |
7 | 36245122121541356 |
oct | 3543577364417721 |
9 | 561255645007632 |
10 | 129999999999953 |
11 | 384707659a8196 |
12 | 126b6a54b75555 |
13 | 576cc41585165 |
14 | 241606819c62d |
15 | 10068e9598788 |
hex | 763bfbd21fd1 |
129999999999953 has 2 divisors, whose sum is σ = 129999999999954. Its totient is φ = 129999999999952.
The previous prime is 129999999999827. The next prime is 129999999999973. The reversal of 129999999999953 is 359999999999921.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 103448569715089 + 26551430284864 = 10170967^2 + 5152808^2 .
It is a cyclic number.
It is not a de Polignac number, because 129999999999953 - 210 = 129999999998929 is a prime.
It is not a weakly prime, because it can be changed into another prime (129999999999973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64999999999976 + 64999999999977.
It is an arithmetic number, because the mean of its divisors is an integer number (64999999999977).
Almost surely, 2129999999999953 is an apocalyptic number.
It is an amenable number.
129999999999953 is a deficient number, since it is larger than the sum of its proper divisors (1).
129999999999953 is an equidigital number, since it uses as much as digits as its factorization.
129999999999953 is an evil number, because the sum of its binary digits is even.
The product of its digits is 941431788270, while the sum is 110.
The spelling of 129999999999953 in words is "one hundred twenty-nine trillion, nine hundred ninety-nine billion, nine hundred ninety-nine million, nine hundred ninety-nine thousand, nine hundred fifty-three".
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