13000101233323 has 2 divisors, whose sum is σ = 13000101233324. Its totient is φ = 13000101233322.

The previous prime is 13000101233309. The next prime is 13000101233387. The reversal of 13000101233323 is 32333210100031.

13000101233323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (32333210100031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13000101233323 - 2⁵ = 13000101233291 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13000101233294 and 13000101233303.

It is not a weakly prime, because it can be changed into another prime (13000101233123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500050616661 + 6500050616662.

It is an arithmetic number, because the mean of its divisors is an integer number (6500050616662).

Almost surely, 2^{13000101233323} is an apocalyptic number.

13000101233323 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000101233323 is an equidigital number, since it uses as much as digits as its factorization.

13000101233323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 13000101233323 its reverse (32333210100031), we get a palindrome (45333311333354).

The spelling of 13000101233323 in words is "thirteen trillion, one hundred one million, two hundred thirty-three thousand, three hundred twenty-three".