Base | Representation |
---|---|
bin | 11101100011110000111000… |
… | …101000000100001010111011 |
3 | 122001021222100121120212212202 |
4 | 131203300320220010022323 |
5 | 114014414042124023032 |
6 | 1140253351051100415 |
7 | 36245156316603251 |
oct | 3543607050041273 |
9 | 561258317525782 |
10 | 130001020142267 |
11 | 3847113982920a |
12 | 126b709a74170b |
13 | 5770074a25471 |
14 | 24161238705d1 |
15 | 1006958e07d62 |
hex | 763c38a042bb |
130001020142267 has 2 divisors, whose sum is σ = 130001020142268. Its totient is φ = 130001020142266.
The previous prime is 130001020142197. The next prime is 130001020142297. The reversal of 130001020142267 is 762241020100031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130001020142267 - 228 = 130000751706811 is a prime.
It is a super-2 number, since 2×1300010201422672 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130001020142297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000510071133 + 65000510071134.
It is an arithmetic number, because the mean of its divisors is an integer number (65000510071134).
Almost surely, 2130001020142267 is an apocalyptic number.
130001020142267 is a deficient number, since it is larger than the sum of its proper divisors (1).
130001020142267 is an equidigital number, since it uses as much as digits as its factorization.
130001020142267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 29.
Adding to 130001020142267 its reverse (762241020100031), we get a palindrome (892242040242298).
The spelling of 130001020142267 in words is "one hundred thirty trillion, one billion, twenty million, one hundred forty-two thousand, two hundred sixty-seven".
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