1300010313211 has 2 divisors, whose sum is σ = 1300010313212. Its totient is φ = 1300010313210.

The previous prime is 1300010313191. The next prime is 1300010313221. The reversal of 1300010313211 is 1123130100031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1300010313211 - 2⁵ = 1300010313179 is a prime.

It is a super-2 number, since 2×1300010313211² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1300010313221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650005156605 + 650005156606.

It is an arithmetic number, because the mean of its divisors is an integer number (650005156606).

Almost surely, 2^{1300010313211} is an apocalyptic number.

1300010313211 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300010313211 is an equidigital number, since it uses as much as digits as its factorization.

1300010313211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1300010313211 its reverse (1123130100031), we get a palindrome (2423140413242).

The spelling of 1300010313211 in words is "one trillion, three hundred billion, ten million, three hundred thirteen thousand, two hundred eleven".