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130001121232091 is a prime number
BaseRepresentation
bin11101100011110000111110…
…101001101100010011011011
3122001021222121122210210001022
4131203300332221230103123
5114014414244013411331
61140253405101513055
736245161655054624
oct3543607651542333
9561258548723038
10130001121232091
11384711908a451a
12126b710857278b
13577008c95b025
142416133066a4b
151006962c2567b
hex763c3ea6c4db

130001121232091 has 2 divisors, whose sum is σ = 130001121232092. Its totient is φ = 130001121232090.

The previous prime is 130001121232043. The next prime is 130001121232109. The reversal of 130001121232091 is 190232121100031.

Together with next prime (130001121232109) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130001121232091 - 218 = 130001120969947 is a prime.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130001121232091.

It is not a weakly prime, because it can be changed into another prime (130001121232991) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000560616045 + 65000560616046.

It is an arithmetic number, because the mean of its divisors is an integer number (65000560616046).

Almost surely, 2130001121232091 is an apocalyptic number.

130001121232091 is a deficient number, since it is larger than the sum of its proper divisors (1).

130001121232091 is an equidigital number, since it uses as much as digits as its factorization.

130001121232091 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 26.

The spelling of 130001121232091 in words is "one hundred thirty trillion, one billion, one hundred twenty-one million, two hundred thirty-two thousand, ninety-one".