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1300011300331 = 4162695057839
BaseRepresentation
bin10010111010101110101…
…101100011010111101011
311121021120000121120100221
4102322232231203113223
5132244410343102311
62433114505510511
7162631330505062
oct22725655432753
94537500546327
101300011300331
11461371540307
1218bb4b1a2437
139578a552b23
1446cc6c8b1d9
1523c39e08671
hex12eaeb635eb

1300011300331 has 8 divisors (see below), whose sum is σ = 1331931585600. Its totient is φ = 1268101143360.

The previous prime is 1300011300319. The next prime is 1300011300361. The reversal of 1300011300331 is 1330031100031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1300011300331 is a prime.

It is a super-2 number, since 2×13000113003312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300011300361) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2271891 + ... + 2785948.

It is an arithmetic number, because the mean of its divisors is an integer number (166491448200).

Almost surely, 21300011300331 is an apocalyptic number.

1300011300331 is a deficient number, since it is larger than the sum of its proper divisors (31920285269).

1300011300331 is an equidigital number, since it uses as much as digits as its factorization.

1300011300331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5064149.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 1300011300331 its reverse (1330031100031), we get a palindrome (2630042400362).

The spelling of 1300011300331 in words is "one trillion, three hundred billion, eleven million, three hundred thousand, three hundred thirty-one".

Divisors: 1 41 6269 257029 5057839 207371399 31707592691 1300011300331