Base | Representation |
---|---|
bin | 10010111010101110110… |
… | …010001111100111001011 |
3 | 11121021120002221001022210 |
4 | 102322232302033213023 |
5 | 132244411201430443 |
6 | 2433114552120203 |
7 | 162631344116346 |
oct | 22725662174713 |
9 | 4537502831283 |
10 | 1300012530123 |
11 | 46137220026a |
12 | 18bb4b696063 |
13 | 9578a893808 |
14 | 46cc70cb45d |
15 | 23c3a09cc33 |
hex | 12eaec8f9cb |
1300012530123 has 4 divisors (see below), whose sum is σ = 1733350040168. Its totient is φ = 866675020080.
The previous prime is 1300012530101. The next prime is 1300012530161. The reversal of 1300012530123 is 3210352100031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1300012530123 - 29 = 1300012529611 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1300012530123.
It is not an unprimeable number, because it can be changed into a prime (1300012530623) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216668755018 + ... + 216668755023.
It is an arithmetic number, because the mean of its divisors is an integer number (433337510042).
Almost surely, 21300012530123 is an apocalyptic number.
1300012530123 is a deficient number, since it is larger than the sum of its proper divisors (433337510045).
1300012530123 is an equidigital number, since it uses as much as digits as its factorization.
1300012530123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 433337510044.
The product of its (nonzero) digits is 540, while the sum is 21.
Adding to 1300012530123 its reverse (3210352100031), we get a palindrome (4510364630154).
The spelling of 1300012530123 in words is "one trillion, three hundred billion, twelve million, five hundred thirty thousand, one hundred twenty-three".
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