Base | Representation |
---|---|
bin | 11101100011110001001111… |
… | …010110001100010100110001 |
3 | 122001022000100011212101022120 |
4 | 131203301033112030110301 |
5 | 114014420332220124131 |
6 | 1140253452545224453 |
7 | 36245201625635520 |
oct | 3543611726142461 |
9 | 561260304771276 |
10 | 130001401333041 |
11 | 38471314a17507 |
12 | 126b7186332129 |
13 | 57701059ac634 |
14 | 241615c33a4b7 |
15 | 100697c603496 |
hex | 763c4f58c531 |
130001401333041 has 16 divisors (see below), whose sum is σ = 206710302741504. Its totient is φ = 71056666566864.
The previous prime is 130001401333009. The next prime is 130001401333043. The reversal of 130001401333041 is 140333104100031.
It is not a de Polignac number, because 130001401333041 - 25 = 130001401333009 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130001401333043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 134577019531 + ... + 134577020496.
It is an arithmetic number, because the mean of its divisors is an integer number (12919393921344).
Almost surely, 2130001401333041 is an apocalyptic number.
It is an amenable number.
130001401333041 is a deficient number, since it is larger than the sum of its proper divisors (76708901408463).
130001401333041 is a wasteful number, since it uses less digits than its factorization.
130001401333041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 269154040060.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 130001401333041 its reverse (140333104100031), we get a palindrome (270334505433072).
The spelling of 130001401333041 in words is "one hundred thirty trillion, one billion, four hundred one million, three hundred thirty-three thousand, forty-one".
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