13000150523 has 4 divisors (see below), whose sum is σ = 13146219720. Its totient is φ = 12854081328.

The previous prime is 13000150519. The next prime is 13000150547. The reversal of 13000150523 is 32505100031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13000150523 - 2² = 13000150519 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13000150495 and 13000150504.

It is not an unprimeable number, because it can be changed into a prime (13000110523) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73034465 + ... + 73034642.

It is an arithmetic number, because the mean of its divisors is an integer number (3286554930).

Almost surely, 2^13000150523 is an apocalyptic number.

13000150523 is a deficient number, since it is larger than the sum of its proper divisors (146069197).

13000150523 is an equidigital number, since it uses as much as digits as its factorization.

13000150523 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 146069196.

The product of its (nonzero) digits is 450, while the sum is 20.

Adding to 13000150523 its reverse (32505100031), we get a palindrome (45505250554).

The spelling of 13000150523 in words is "thirteen billion, one hundred fifty thousand, five hundred twenty-three".