1300020193 has 2 divisors, whose sum is σ = 1300020194. Its totient is φ = 1300020192.

The previous prime is 1300020181. The next prime is 1300020203. The reversal of 1300020193 is 3910200031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1092170304 + 207849889 = 33048^2 + 14417^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1300020193 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1300020193.

It is not a weakly prime, because it can be changed into another prime (1300020143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650010096 + 650010097.

It is an arithmetic number, because the mean of its divisors is an integer number (650010097).

Almost surely, 2^1300020193 is an apocalyptic number.

It is an amenable number.

1300020193 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300020193 is an equidigital number, since it uses as much as digits as its factorization.

1300020193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

The square root of 1300020193 is about 36055.7927800790. The cubic root of 1300020193 is about 1091.3985339284.

The spelling of 1300020193 in words is "one billion, three hundred million, twenty thousand, one hundred ninety-three".