Base | Representation |
---|---|
bin | 11101100011110001110100… |
… | …111001010111010110001111 |
3 | 122001022001222002021112112210 |
4 | 131203301310321113112033 |
5 | 114014423130003411343 |
6 | 1140254035252001503 |
7 | 36245223345436632 |
oct | 3543616471272617 |
9 | 561261862245483 |
10 | 130002031310223 |
11 | 3847160858a706 |
12 | 126b7321300293 |
13 | 57701a63729b7 |
14 | 24161bbc87c19 |
15 | 10069b7a93333 |
hex | 763c74e5758f |
130002031310223 has 16 divisors (see below), whose sum is σ = 178938665358336. Its totient is φ = 83867057142720.
The previous prime is 130002031310191. The next prime is 130002031310231. The reversal of 130002031310223 is 322013130200031.
It is not a de Polignac number, because 130002031310223 - 25 = 130002031310191 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130002031310223.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130002031314223) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42007086 + ... + 44995547.
It is an arithmetic number, because the mean of its divisors is an integer number (11183666584896).
Almost surely, 2130002031310223 is an apocalyptic number.
130002031310223 is a deficient number, since it is larger than the sum of its proper divisors (48936634048113).
130002031310223 is a wasteful number, since it uses less digits than its factorization.
130002031310223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87018734.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 130002031310223 its reverse (322013130200031), we get a palindrome (452015161510254).
The spelling of 130002031310223 in words is "one hundred thirty trillion, two billion, thirty-one million, three hundred ten thousand, two hundred twenty-three".
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