Base | Representation |
---|---|
bin | 111100100010010111… |
… | …0011011010011010111 |
3 | 110102120001202220000020 |
4 | 1321010232123103113 |
5 | 4112221010240043 |
6 | 135415550520223 |
7 | 12251400051642 |
oct | 1710456332327 |
9 | 412501686006 |
10 | 130002040023 |
11 | 501518428a9 |
12 | 21241506073 |
13 | c34a43a24b |
14 | 641387aa59 |
15 | 35ad117e83 |
hex | 1e44b9b4d7 |
130002040023 has 16 divisors (see below), whose sum is σ = 174479923200. Its totient is φ = 86097323520.
The previous prime is 130002040009. The next prime is 130002040073. The reversal of 130002040023 is 320040200031.
It is not a de Polignac number, because 130002040023 - 218 = 130001777879 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130002039984 and 130002040011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130002040073) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 269943 + ... + 576951.
It is an arithmetic number, because the mean of its divisors is an integer number (10904995200).
Almost surely, 2130002040023 is an apocalyptic number.
130002040023 is a deficient number, since it is larger than the sum of its proper divisors (44477883177).
130002040023 is a wasteful number, since it uses less digits than its factorization.
130002040023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 307942.
The product of its (nonzero) digits is 144, while the sum is 15.
Adding to 130002040023 its reverse (320040200031), we get a palindrome (450042240054).
The spelling of 130002040023 in words is "one hundred thirty billion, two million, forty thousand, twenty-three".
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