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1300020554013 = 337891311004537
BaseRepresentation
bin10010111010101111010…
…000110110100100011101
311121021120200000201000220
4102322233100312210131
5132244420230212023
62433115440111553
7162631502245536
oct22725720664435
94537520021026
101300020554013
11461376790785
1218bb523055b9
139578c442a8c
1446cc81b968d
1523c3ab353e3
hex12eaf43691d

1300020554013 has 32 divisors (see below), whose sum is σ = 1813954538880. Its totient is φ = 827416212480.

The previous prime is 1300020553969. The next prime is 1300020554033. The reversal of 1300020554013 is 3104550200031.

It is not a de Polignac number, because 1300020554013 - 232 = 1295725586717 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300020554033) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 791881 + ... + 1796417.

It is an arithmetic number, because the mean of its divisors is an integer number (56686079340).

Almost surely, 21300020554013 is an apocalyptic number.

It is an amenable number.

1300020554013 is a deficient number, since it is larger than the sum of its proper divisors (513933984867).

1300020554013 is a wasteful number, since it uses less digits than its factorization.

1300020554013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1004797.

The product of its (nonzero) digits is 1800, while the sum is 24.

Adding to 1300020554013 its reverse (3104550200031), we get a palindrome (4404570754044).

The spelling of 1300020554013 in words is "one trillion, three hundred billion, twenty million, five hundred fifty-four thousand, thirteen".

Divisors: 1 3 37 89 111 131 267 393 3293 4847 9879 11659 14541 34977 431383 1004537 1294149 3013611 37167869 89403793 111503607 131594347 268211379 394783041 3307940341 4868990839 9923821023 11711896883 14606972517 35135690649 433340184671 1300020554013