130002243455433 has 8 divisors (see below), whose sum is σ = 173362191866496. Its totient is φ = 86655228674000.

The previous prime is 130002243455423. The next prime is 130002243455473. The reversal of 130002243455433 is 334554342200031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130002243455433 - 2¹⁰ = 130002243454409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130002243455391 and 130002243455400.

It is not an unprimeable number, because it can be changed into a prime (130002243455423) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3233383953 + ... + 3233424158.

It is an arithmetic number, because the mean of its divisors is an integer number (21670273983312).

Almost surely, 2^{130002243455433} is an apocalyptic number.

It is an amenable number.

130002243455433 is a deficient number, since it is larger than the sum of its proper divisors (43359948411063).

130002243455433 is an equidigital number, since it uses as much as digits as its factorization.

130002243455433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6466814815.

The product of its (nonzero) digits is 518400, while the sum is 39.

Adding to 130002243455433 its reverse (334554342200031), we get a palindrome (464556585655464).

The spelling of 130002243455433 in words is "one hundred thirty trillion, two billion, two hundred forty-three million, four hundred fifty-five thousand, four hundred thirty-three".