Base | Representation |
---|---|
bin | 111100100010010111… |
… | …1011101111100110010 |
3 | 110102120002021202110212 |
4 | 1321010233131330302 |
5 | 4112221043004020 |
6 | 135420000424122 |
7 | 12251402266553 |
oct | 1710457357462 |
9 | 412502252425 |
10 | 130002313010 |
11 | 50151a09a09 |
12 | 21241618042 |
13 | c34a50458b |
14 | 641390c32a |
15 | 35ad16dcc5 |
hex | 1e44bddf32 |
130002313010 has 64 divisors (see below), whose sum is σ = 239078044800. Its totient is φ = 50884872192.
The previous prime is 130002313009. The next prime is 130002313081. The reversal of 130002313010 is 10313200031.
130002313010 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×1300023130103 (a number of 34 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 103257761 + ... + 103259019.
It is an arithmetic number, because the mean of its divisors is an integer number (3735594450).
Almost surely, 2130002313010 is an apocalyptic number.
130002313010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130002313010 is a deficient number, since it is larger than the sum of its proper divisors (109075731790).
130002313010 is a wasteful number, since it uses less digits than its factorization.
130002313010 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2235.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 130002313010 its reverse (10313200031), we get a palindrome (140315513041).
The spelling of 130002313010 in words is "one hundred thirty billion, two million, three hundred thirteen thousand, ten".
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