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1300030232122 = 24115854027221
BaseRepresentation
bin10010111010101111110…
…101110001011000111010
311121021121100020101220101
4102322233311301120322
5132244430214411442
62433120423350014
7162631650434566
oct22725765613072
94537540211811
101300030232122
114613811a1016
1218bb555b230a
1395791450c7b
1446cc95b86a6
1523c3b8e7cb7
hex12eafd7163a

1300030232122 has 8 divisors (see below), whose sum is σ = 1997607429972. Its totient is φ = 634161088800.

The previous prime is 1300030232099. The next prime is 1300030232129. The reversal of 1300030232122 is 2212320300031.

It can be written as a sum of positive squares in 2 ways, for example, as 1106895472281 + 193134759841 = 1052091^2 + 439471^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-5 number, since 5×13000302321225 (a number of 62 digits) contains 55555 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1300030232122.

It is not an unprimeable number, because it can be changed into a prime (1300030232129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7927013529 + ... + 7927013692.

Almost surely, 21300030232122 is an apocalyptic number.

1300030232122 is a deficient number, since it is larger than the sum of its proper divisors (697577197850).

1300030232122 is a wasteful number, since it uses less digits than its factorization.

1300030232122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15854027264.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 1300030232122 its reverse (2212320300031), we get a palindrome (3512350532153).

The spelling of 1300030232122 in words is "one trillion, three hundred billion, thirty million, two hundred thirty-two thousand, one hundred twenty-two".

Divisors: 1 2 41 82 15854027221 31708054442 650015116061 1300030232122