Base | Representation |
---|---|
bin | 1011110100101101111011… |
… | …1111000001000101011011 |
3 | 1201000211002002202210211202 |
4 | 2331023132333001011123 |
5 | 3200444114344133123 |
6 | 43352132205544415 |
7 | 2511145565402444 |
oct | 275133677010533 |
9 | 51024062683752 |
10 | 13000312099163 |
11 | 4162446298494 |
12 | 155b66a27510b |
13 | 733c0253138c |
14 | 32d30b6682cb |
15 | 17827bc85a28 |
hex | bd2defc115b |
13000312099163 has 2 divisors, whose sum is σ = 13000312099164. Its totient is φ = 13000312099162.
The previous prime is 13000312099129. The next prime is 13000312099213. The reversal of 13000312099163 is 36199021300031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13000312099163 - 228 = 13000043663707 is a prime.
It is a super-2 number, since 2×130003120991632 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13000312099763) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500156049581 + 6500156049582.
It is an arithmetic number, because the mean of its divisors is an integer number (6500156049582).
Almost surely, 213000312099163 is an apocalyptic number.
13000312099163 is a deficient number, since it is larger than the sum of its proper divisors (1).
13000312099163 is an equidigital number, since it uses as much as digits as its factorization.
13000312099163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26244, while the sum is 38.
Adding to 13000312099163 its reverse (36199021300031), we get a palindrome (49199333399194).
The spelling of 13000312099163 in words is "thirteen trillion, three hundred twelve million, ninety-nine thousand, one hundred sixty-three".
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