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1300031320001 is a prime number
BaseRepresentation
bin10010111010101111111…
…001111010111111000001
311121021121102021200012012
4102322233321322333001
5132244431004220001
62433120502542305
7162631662615341
oct22725771727701
94537542250165
101300031320001
11461381874397
1218bb55a37995
139579174219b
1446cc97bcd21
1523c3ba602bb
hex12eafe7afc1

1300031320001 has 2 divisors, whose sum is σ = 1300031320002. Its totient is φ = 1300031320000.

The previous prime is 1300031319959. The next prime is 1300031320019. The reversal of 1300031320001 is 1000231300031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 912026910001 + 388004410000 = 955001^2 + 622900^2 .

It is an emirp because it is prime and its reverse (1000231300031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1300031320001 - 226 = 1299964211137 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1300031320031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650015660000 + 650015660001.

It is an arithmetic number, because the mean of its divisors is an integer number (650015660001).

Almost surely, 21300031320001 is an apocalyptic number.

It is an amenable number.

1300031320001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300031320001 is an equidigital number, since it uses as much as digits as its factorization.

1300031320001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 1300031320001 its reverse (1000231300031), we get a palindrome (2300262620032).

The spelling of 1300031320001 in words is "one trillion, three hundred billion, thirty-one million, three hundred twenty thousand, one".