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130003161 = 343334387
BaseRepresentation
bin1111011111110…
…11000011011001
3100001121211210220
413233323003121
5231240100121
620522230253
73136002651
oct757730331
9301554726
10130003161
1167424332
1237655389
1320c1a062
14133a1361
15b62e6c6
hex7bfb0d9

130003161 has 4 divisors (see below), whose sum is σ = 173337552. Its totient is φ = 86668772.

The previous prime is 130003129. The next prime is 130003177. The reversal of 130003161 is 161300031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130003161 - 25 = 130003129 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130003161.

It is not an unprimeable number, because it can be changed into a prime (130003121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21667191 + ... + 21667196.

It is an arithmetic number, because the mean of its divisors is an integer number (43334388).

Almost surely, 2130003161 is an apocalyptic number.

It is an amenable number.

130003161 is a deficient number, since it is larger than the sum of its proper divisors (43334391).

130003161 is an equidigital number, since it uses as much as digits as its factorization.

130003161 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43334390.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 130003161 is about 11401.8928691687. The cubic root of 130003161 is about 506.5838077702.

Adding to 130003161 its reverse (161300031), we get a palindrome (291303192).

It can be divided in two parts, 13000 and 3161, that added together give a palindrome (16161).

The spelling of 130003161 in words is "one hundred thirty million, three thousand, one hundred sixty-one".

Divisors: 1 3 43334387 130003161