13000320000033 has 4 divisors (see below), whose sum is σ = 17333760000048. Its totient is φ = 8666880000020.

The previous prime is 13000320000023. The next prime is 13000320000043. The reversal of 13000320000033 is 33000002300031.

13000320000033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (13000320000023) and next prime (13000320000043).

It is a cyclic number.

It is not a de Polignac number, because 13000320000033 - 2¹² = 13000319995937 is a prime.

It is a super-2 number, since 2×13000320000033² (a number of 27 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13000319999967 and 13000320000021.

It is not an unprimeable number, because it can be changed into a prime (13000320000023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2166720000003 + ... + 2166720000008.

It is an arithmetic number, because the mean of its divisors is an integer number (4333440000012).

Almost surely, 2^{13000320000033} is an apocalyptic number.

It is an amenable number.

13000320000033 is a deficient number, since it is larger than the sum of its proper divisors (4333440000015).

13000320000033 is an equidigital number, since it uses as much as digits as its factorization.

13000320000033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4333440000014.

The product of its (nonzero) digits is 162, while the sum is 15.

Adding to 13000320000033 its reverse (33000002300031), we get a palindrome (46000322300064).

The spelling of 13000320000033 in words is "thirteen trillion, three hundred twenty million, thirty-three", and thus it is an aban number.