Base | Representation |
---|---|
bin | 111100100010011001… |
… | …1011001101111000001 |
3 | 110102120011020011011120 |
4 | 1321010303121233001 |
5 | 4112221324004241 |
6 | 135420034502453 |
7 | 12251414123364 |
oct | 1710463315701 |
9 | 412504204146 |
10 | 130003344321 |
11 | 50152553834 |
12 | 21241a34a29 |
13 | c34a7a5b16 |
14 | 6413ada0db |
15 | 35ad2c4666 |
hex | 1e44cd9bc1 |
130003344321 has 8 divisors (see below), whose sum is σ = 173626210464. Its totient is φ = 86524687200.
The previous prime is 130003344319. The next prime is 130003344329. The reversal of 130003344321 is 123443300031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 130003344321 - 21 = 130003344319 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130003344291 and 130003344300.
It is not an unprimeable number, because it can be changed into a prime (130003344329) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36050151 + ... + 36053756.
It is an arithmetic number, because the mean of its divisors is an integer number (21703276308).
Almost surely, 2130003344321 is an apocalyptic number.
It is an amenable number.
130003344321 is a deficient number, since it is larger than the sum of its proper divisors (43622866143).
130003344321 is an equidigital number, since it uses as much as digits as its factorization.
130003344321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 72104511.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 130003344321 its reverse (123443300031), we get a palindrome (253446644352).
The spelling of 130003344321 in words is "one hundred thirty billion, three million, three hundred forty-four thousand, three hundred twenty-one".
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