13000341403 has 8 divisors (see below), whose sum is σ = 15203057408. Its totient is φ = 10884006504.

The previous prime is 13000341391. The next prime is 13000341407. The reversal of 13000341403 is 30414300031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2^k-13000341403 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13000341407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21594951 + ... + 21595552.

It is an arithmetic number, because the mean of its divisors is an integer number (1900382176).

Almost surely, 2^13000341403 is an apocalyptic number.

13000341403 is a deficient number, since it is larger than the sum of its proper divisors (2202716005).

13000341403 is an equidigital number, since it uses as much as digits as its factorization.

13000341403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43190553.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 13000341403 its reverse (30414300031), we get a palindrome (43414641434).

The spelling of 13000341403 in words is "thirteen billion, three hundred forty-one thousand, four hundred three".