Base | Representation |
---|---|
bin | 100110101111101… |
… | …0001011101101111 |
3 | 10100121021001121010 |
4 | 1031133101131233 |
5 | 10130302344011 |
6 | 333000240303 |
7 | 44134121445 |
oct | 11537213557 |
9 | 3317231533 |
10 | 1300043631 |
11 | 607928027 |
12 | 303470093 |
13 | 179451ab3 |
14 | c4932b95 |
15 | 791ed1a6 |
hex | 4d7d176f |
1300043631 has 16 divisors (see below), whose sum is σ = 1825577600. Its totient is φ = 820650528.
The previous prime is 1300043617. The next prime is 1300043677. The reversal of 1300043631 is 1363400031.
It is not a de Polignac number, because 1300043631 - 25 = 1300043599 is a prime.
It is a super-2 number, since 2×13000436312 = 3380226885007328322, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1300043598 and 1300043607.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1300043611) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 131400 + ... + 140946.
It is an arithmetic number, because the mean of its divisors is an integer number (114098600).
Almost surely, 21300043631 is an apocalyptic number.
1300043631 is a deficient number, since it is larger than the sum of its proper divisors (525533969).
1300043631 is a wasteful number, since it uses less digits than its factorization.
1300043631 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11958.
The product of its (nonzero) digits is 648, while the sum is 21.
The square root of 1300043631 is about 36056.1178026698. The cubic root of 1300043631 is about 1091.4050928124.
Adding to 1300043631 its reverse (1363400031), we get a palindrome (2663443662).
The spelling of 1300043631 in words is "one billion, three hundred million, forty-three thousand, six hundred thirty-one".
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