Base | Representation |
---|---|
bin | 10010111010110001111… |
… | …111011001111011111011 |
3 | 11121021200212010110002121 |
4 | 102322301333121323323 |
5 | 132300013433440211 |
6 | 2433124152542111 |
7 | 162632566214542 |
oct | 22726177317373 |
9 | 4537625113077 |
10 | 1300066311931 |
11 | 46139a5a4342 |
12 | 18bb656b1937 |
13 | 95798a7437a |
14 | 46cd02cb159 |
15 | 23c3eb73271 |
hex | 12eb1fd9efb |
1300066311931 has 2 divisors, whose sum is σ = 1300066311932. Its totient is φ = 1300066311930.
The previous prime is 1300066311893. The next prime is 1300066311941. The reversal of 1300066311931 is 1391136600031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1300066311931 is a prime.
It is a super-2 number, since 2×13000663119312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1300066311941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650033155965 + 650033155966.
It is an arithmetic number, because the mean of its divisors is an integer number (650033155966).
Almost surely, 21300066311931 is an apocalyptic number.
1300066311931 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300066311931 is an equidigital number, since it uses as much as digits as its factorization.
1300066311931 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 34.
The spelling of 1300066311931 in words is "one trillion, three hundred billion, sixty-six million, three hundred eleven thousand, nine hundred thirty-one".
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