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1300101133273 is a prime number
BaseRepresentation
bin10010111010110100000…
…100001111001111011001
311121021210021122112222221
4102322310010033033121
5132300101342231043
62433131435144041
7162633501203515
oct22726404171731
94537707575887
101300101133273
11461408218108
1218bb752a5021
13957a3046a07
1446cd4b93145
1523c42c508ed
hex12eb410f3d9

1300101133273 has 2 divisors, whose sum is σ = 1300101133274. Its totient is φ = 1300101133272.

The previous prime is 1300101133259. The next prime is 1300101133283. The reversal of 1300101133273 is 3723311010031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 939953518144 + 360147615129 = 969512^2 + 600123^2 .

It is an emirp because it is prime and its reverse (3723311010031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1300101133273 - 237 = 1162662179801 is a prime.

It is not a weakly prime, because it can be changed into another prime (1300101133213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650050566636 + 650050566637.

It is an arithmetic number, because the mean of its divisors is an integer number (650050566637).

Almost surely, 21300101133273 is an apocalyptic number.

It is an amenable number.

1300101133273 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300101133273 is an equidigital number, since it uses as much as digits as its factorization.

1300101133273 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1134, while the sum is 25.

The spelling of 1300101133273 in words is "one trillion, three hundred billion, one hundred one million, one hundred thirty-three thousand, two hundred seventy-three".