Base | Representation |
---|---|
bin | 111100100010101000… |
… | …0101010011101011011 |
3 | 110102120200122212100220 |
4 | 1321011100222131123 |
5 | 4112230304440003 |
6 | 135420511131123 |
7 | 12251536252032 |
oct | 1710520523533 |
9 | 412520585326 |
10 | 130011015003 |
11 | 50156912941 |
12 | 21244513aa3 |
13 | c34c26039c |
14 | 6414b35719 |
15 | 35adcdc353 |
hex | 1e4542a75b |
130011015003 has 8 divisors (see below), whose sum is σ = 173351001600. Its totient is φ = 86672519208.
The previous prime is 130011014983. The next prime is 130011015031. The reversal of 130011015003 is 300510110031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 130011015003 - 29 = 130011014491 is a prime.
It is a super-2 number, since 2×1300110150032 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (130011015083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 150243 + ... + 531596.
It is an arithmetic number, because the mean of its divisors is an integer number (21668875200).
Almost surely, 2130011015003 is an apocalyptic number.
130011015003 is a deficient number, since it is larger than the sum of its proper divisors (43339986597).
130011015003 is an equidigital number, since it uses as much as digits as its factorization.
130011015003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 745401.
The product of its (nonzero) digits is 45, while the sum is 15.
Adding to 130011015003 its reverse (300510110031), we get a palindrome (430521125034).
The spelling of 130011015003 in words is "one hundred thirty billion, eleven million, fifteen thousand, three".
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