Base | Representation |
---|---|
bin | 10010111010110100100… |
… | …110110100110011000011 |
3 | 11121021210220201012012202 |
4 | 102322310212310303003 |
5 | 132300111202400003 |
6 | 2433132401343415 |
7 | 162633641235236 |
oct | 22726446646303 |
9 | 4537726635182 |
10 | 1300110200003 |
11 | 46141235007a |
12 | 18bb78337b6b |
13 | 957a4b9c844 |
14 | 46cd607341d |
15 | 23c43942088 |
hex | 12eb49b4cc3 |
1300110200003 has 32 divisors (see below), whose sum is σ = 1387031592960. Its totient is φ = 1216556288640.
The previous prime is 1300110199963. The next prime is 1300110200023. The reversal of 1300110200003 is 3000020110031.
It is a cyclic number.
It is not a de Polignac number, because 1300110200003 - 28 = 1300110199747 is a prime.
It is a super-2 number, since 2×13001102000032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1300110200023) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 93640700 + ... + 93654582.
It is an arithmetic number, because the mean of its divisors is an integer number (43344737280).
Almost surely, 21300110200003 is an apocalyptic number.
1300110200003 is a deficient number, since it is larger than the sum of its proper divisors (86921392957).
1300110200003 is a wasteful number, since it uses less digits than its factorization.
1300110200003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14627.
The product of its (nonzero) digits is 18, while the sum is 11.
Adding to 1300110200003 its reverse (3000020110031), we get a palindrome (4300130310034).
The spelling of 1300110200003 in words is "one trillion, three hundred billion, one hundred ten million, two hundred thousand, three".
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