130011042121 has 4 divisors (see below), whose sum is σ = 130022714500. Its totient is φ = 129999369744.

The previous prime is 130011042097. The next prime is 130011042131. The reversal of 130011042121 is 121240110031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 121240110031 = 8221 ⋅14747611.

It can be written as a sum of positive squares in 2 ways, for example, as 38834220096 + 91176822025 = 197064^2 + 301955^2 .

It is a cyclic number.

It is not a de Polignac number, because 130011042121 - 2²³ = 130002653513 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130011042095 and 130011042104.

It is not an unprimeable number, because it can be changed into a prime (130011042131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5819466 + ... + 5841763.

It is an arithmetic number, because the mean of its divisors is an integer number (32505678625).

Almost surely, 2^130011042121 is an apocalyptic number.

It is an amenable number.

130011042121 is a deficient number, since it is larger than the sum of its proper divisors (11672379).

130011042121 is a wasteful number, since it uses less digits than its factorization.

130011042121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11672378.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 130011042121 its reverse (121240110031), we get a palindrome (251251152152).

The spelling of 130011042121 in words is "one hundred thirty billion, eleven million, forty-two thousand, one hundred twenty-one".