Search a number
-
+
130011100113 = 3151287000221
BaseRepresentation
bin111100100010101000…
…0111111001111010001
3110102120200211012010010
41321011100333033101
54112230320200423
6135420513025133
712251540055126
oct1710520771721
9412520735103
10130011100113
1150156970884
12212445551a9
13c34c29004b
146414b5874d
1535add07693
hex1e4543f3d1

130011100113 has 8 divisors (see below), whose sum is σ = 174496134976. Its totient is φ = 86100066000.

The previous prime is 130011100111. The next prime is 130011100133. The reversal of 130011100113 is 311001110031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 130011100113 - 21 = 130011100111 is a prime.

It is a super-2 number, since 2×1300111001132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130011100111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 143499658 + ... + 143500563.

It is an arithmetic number, because the mean of its divisors is an integer number (21812016872).

Almost surely, 2130011100113 is an apocalyptic number.

It is an amenable number.

130011100113 is a deficient number, since it is larger than the sum of its proper divisors (44485034863).

130011100113 is a wasteful number, since it uses less digits than its factorization.

130011100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 287000375.

The product of its (nonzero) digits is 9, while the sum is 12.

Adding to 130011100113 its reverse (311001110031), we get a palindrome (441012210144).

The spelling of 130011100113 in words is "one hundred thirty billion, eleven million, one hundred thousand, one hundred thirteen".

Divisors: 1 3 151 453 287000221 861000663 43337033371 130011100113