Base | Representation |
---|---|
bin | 11101100011111010011101… |
… | …111100110011001101001011 |
3 | 122001022221220201210101102221 |
4 | 131203322131330303031023 |
5 | 114020101130330324321 |
6 | 1140302212110434511 |
7 | 36246002314211206 |
oct | 3543723574631513 |
9 | 561287821711387 |
10 | 130011310011211 |
11 | 3847553a128032 |
12 | 126b9090802a37 |
13 | 57710247a4305 |
14 | 241681c2ca93d |
15 | 1006d5c472e41 |
hex | 763e9df3334b |
130011310011211 has 2 divisors, whose sum is σ = 130011310011212. Its totient is φ = 130011310011210.
The previous prime is 130011310011197. The next prime is 130011310011217. The reversal of 130011310011211 is 112110013110031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130011310011211 is a prime.
It is not a weakly prime, because it can be changed into another prime (130011310011217) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005655005605 + 65005655005606.
It is an arithmetic number, because the mean of its divisors is an integer number (65005655005606).
Almost surely, 2130011310011211 is an apocalyptic number.
130011310011211 is a deficient number, since it is larger than the sum of its proper divisors (1).
130011310011211 is an equidigital number, since it uses as much as digits as its factorization.
130011310011211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 16.
Adding to 130011310011211 its reverse (112110013110031), we get a palindrome (242121323121242).
The spelling of 130011310011211 in words is "one hundred thirty trillion, eleven billion, three hundred ten million, eleven thousand, two hundred eleven".
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