13001153000001 has 8 divisors (see below), whose sum is σ = 17334950710560. Its totient is φ = 8667395311392.

The previous prime is 13001152999979. The next prime is 13001153000027. The reversal of 13001153000001 is 10000035110031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13001153000001 - 2¹⁴ = 13001152983617 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13001153000081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9239116 + ... + 10552893.

It is an arithmetic number, because the mean of its divisors is an integer number (2166868838820).

Almost surely, 2^{13001153000001} is an apocalyptic number.

It is an amenable number.

13001153000001 is a deficient number, since it is larger than the sum of its proper divisors (4333797710559).

13001153000001 is a wasteful number, since it uses less digits than its factorization.

13001153000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20010975.

The product of its (nonzero) digits is 45, while the sum is 15.

Adding to 13001153000001 its reverse (10000035110031), we get a palindrome (23001188110032).

The spelling of 13001153000001 in words is "thirteen trillion, one billion, one hundred fifty-three million, one", and thus it is an aban number.