Base | Representation |
---|---|
bin | 100110101111110… |
… | …0100001001010011 |
3 | 10100121101221120001 |
4 | 1031133210021103 |
5 | 10130312321042 |
6 | 333002030431 |
7 | 44134560514 |
oct | 11537441123 |
9 | 3317357501 |
10 | 1300120147 |
11 | 60797a567 |
12 | 3034a8417 |
13 | 17947a881 |
14 | c4952a0b |
15 | 79215bb7 |
hex | 4d7e4253 |
1300120147 has 2 divisors, whose sum is σ = 1300120148. Its totient is φ = 1300120146.
The previous prime is 1300120123. The next prime is 1300120153. The reversal of 1300120147 is 7410210031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1300120147 is a prime.
It is not a weakly prime, because it can be changed into another prime (1300120187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650060073 + 650060074.
It is an arithmetic number, because the mean of its divisors is an integer number (650060074).
Almost surely, 21300120147 is an apocalyptic number.
1300120147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300120147 is an equidigital number, since it uses as much as digits as its factorization.
1300120147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168, while the sum is 19.
The square root of 1300120147 is about 36057.1788552571. The cubic root of 1300120147 is about 1091.4265044819.
Adding to 1300120147 its reverse (7410210031), we get a palindrome (8710330178).
The spelling of 1300120147 in words is "one billion, three hundred million, one hundred twenty thousand, one hundred forty-seven".
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