Base | Representation |
---|---|
bin | 11101100011111011001001… |
… | …000010111100111001110011 |
3 | 122001100000210010022021002012 |
4 | 131203323021002330321303 |
5 | 114020104120424402313 |
6 | 1140302411535513135 |
7 | 36246026243662601 |
oct | 3543731102747163 |
9 | 561300703267065 |
10 | 130012033044083 |
11 | 38475880279363 |
12 | 126b92529887ab |
13 | 577110b519408 |
14 | 241688a33c871 |
15 | 1006da0b94da8 |
hex | 763ec90bce73 |
130012033044083 has 2 divisors, whose sum is σ = 130012033044084. Its totient is φ = 130012033044082.
The previous prime is 130012033044037. The next prime is 130012033044107. The reversal of 130012033044083 is 380440330210031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130012033044083 - 234 = 129994853174899 is a prime.
It is not a weakly prime, because it can be changed into another prime (130012033044583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006016522041 + 65006016522042.
It is an arithmetic number, because the mean of its divisors is an integer number (65006016522042).
Almost surely, 2130012033044083 is an apocalyptic number.
130012033044083 is a deficient number, since it is larger than the sum of its proper divisors (1).
130012033044083 is an equidigital number, since it uses as much as digits as its factorization.
130012033044083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 32.
The spelling of 130012033044083 in words is "one hundred thirty trillion, twelve billion, thirty-three million, forty-four thousand, eighty-three".
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