Base | Representation |
---|---|
bin | 10010111010110101010… |
… | …000100001111111001001 |
3 | 11121021211200021122110121 |
4 | 102322311100201333021 |
5 | 132300122002224001 |
6 | 2433133431543241 |
7 | 162634133201665 |
oct | 22726520417711 |
9 | 4537750248417 |
10 | 1300121133001 |
11 | 461418538209 |
12 | 18bb7bb2ab21 |
13 | 957a7229c82 |
14 | 46cd76bb8a5 |
15 | 23c448a16a1 |
hex | 12eb5421fc9 |
1300121133001 has 2 divisors, whose sum is σ = 1300121133002. Its totient is φ = 1300121133000.
The previous prime is 1300121132993. The next prime is 1300121133023. The reversal of 1300121133001 is 1003311210031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1298571923401 + 1549209600 = 1139549^2 + 39360^2 .
It is a cyclic number.
It is not a de Polignac number, because 1300121133001 - 23 = 1300121132993 is a prime.
It is not a weakly prime, because it can be changed into another prime (1300121137001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650060566500 + 650060566501.
It is an arithmetic number, because the mean of its divisors is an integer number (650060566501).
Almost surely, 21300121133001 is an apocalyptic number.
It is an amenable number.
1300121133001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300121133001 is an equidigital number, since it uses as much as digits as its factorization.
1300121133001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1300121133001 its reverse (1003311210031), we get a palindrome (2303432343032).
The spelling of 1300121133001 in words is "one trillion, three hundred billion, one hundred twenty-one million, one hundred thirty-three thousand, one".
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