Base | Representation |
---|---|
bin | 111100100010101010… |
… | …0111110000110101001 |
3 | 110102120202210020010010 |
4 | 1321011110332012221 |
5 | 4112231102102131 |
6 | 135420551242133 |
7 | 12251551663503 |
oct | 1710524760651 |
9 | 412522706103 |
10 | 130012144041 |
11 | 5015751412a |
12 | 21244979349 |
13 | c34c567260 |
14 | 6414d4ad73 |
15 | 35ade61b46 |
hex | 1e4553e1a9 |
130012144041 has 16 divisors (see below), whose sum is σ = 186803023680. Its totient is φ = 79956507840.
The previous prime is 130012143979. The next prime is 130012144063. The reversal of 130012144041 is 140441210031.
It is not a de Polignac number, because 130012144041 - 26 = 130012143977 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130012143999 and 130012144017.
It is not an unprimeable number, because it can be changed into a prime (130012144081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 999726 + ... + 1122263.
It is an arithmetic number, because the mean of its divisors is an integer number (11675188980).
Almost surely, 2130012144041 is an apocalyptic number.
It is an amenable number.
130012144041 is a deficient number, since it is larger than the sum of its proper divisors (56790879639).
130012144041 is a wasteful number, since it uses less digits than its factorization.
130012144041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2123576.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 130012144041 its reverse (140441210031), we get a palindrome (270453354072).
The spelling of 130012144041 in words is "one hundred thirty billion, twelve million, one hundred forty-four thousand, forty-one".
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