Base | Representation |
---|---|
bin | 111100100010101010… |
… | …1001100010011100011 |
3 | 110102120202220011220120 |
4 | 1321011111030103203 |
5 | 4112231110432321 |
6 | 135420552411323 |
7 | 12251552325213 |
oct | 1710525142343 |
9 | 412522804816 |
10 | 130012202211 |
11 | 50157553901 |
12 | 212449a6b43 |
13 | c34c587888 |
14 | 6414d64243 |
15 | 35ade73ec6 |
hex | 1e4554c4e3 |
130012202211 has 8 divisors (see below), whose sum is σ = 178034727504. Its totient is φ = 84332239200.
The previous prime is 130012202191. The next prime is 130012202219. The reversal of 130012202211 is 112202210031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 130012202211 - 213 = 130012194019 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130012202219) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 585640440 + ... + 585640661.
It is an arithmetic number, because the mean of its divisors is an integer number (22254340938).
Almost surely, 2130012202211 is an apocalyptic number.
130012202211 is a deficient number, since it is larger than the sum of its proper divisors (48022525293).
130012202211 is a wasteful number, since it uses less digits than its factorization.
130012202211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1171281141.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 130012202211 its reverse (112202210031), we get a palindrome (242214412242).
The spelling of 130012202211 in words is "one hundred thirty billion, twelve million, two hundred two thousand, two hundred eleven".
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