Base | Representation |
---|---|
bin | 11101100011111011010100… |
… | …111011000011111000101011 |
3 | 122001100001022000020121201121 |
4 | 131203323110323003320223 |
5 | 114020110022432131443 |
6 | 1140302443414400111 |
7 | 36246034213440043 |
oct | 3543732473037053 |
9 | 561301260217647 |
10 | 130012232302123 |
11 | 384759727a4926 |
12 | 126b92a9660037 |
13 | 57711408a3a92 |
14 | 24168a89aa723 |
15 | 1006db34044ed |
hex | 763ed4ec3e2b |
130012232302123 has 4 divisors (see below), whose sum is σ = 130277022999768. Its totient is φ = 129747441604480.
The previous prime is 130012232302111. The next prime is 130012232302157. The reversal of 130012232302123 is 321203232210031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130012232302123 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130012232309123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132395348086 + ... + 132395349067.
It is an arithmetic number, because the mean of its divisors is an integer number (32569255749942).
Almost surely, 2130012232302123 is an apocalyptic number.
130012232302123 is a deficient number, since it is larger than the sum of its proper divisors (264790697645).
130012232302123 is an equidigital number, since it uses as much as digits as its factorization.
130012232302123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 264790697644.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 130012232302123 its reverse (321203232210031), we get a palindrome (451215464512154).
The spelling of 130012232302123 in words is "one hundred thirty trillion, twelve billion, two hundred thirty-two million, three hundred two thousand, one hundred twenty-three".
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