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130012332401 = 718573190343
BaseRepresentation
bin111100100010101010…
…1101100000101110001
3110102120210010210111102
41321011111230011301
54112231124114101
6135420555254145
712251553406610
oct1710525540561
9412523123442
10130012332401
11501576326a6
1221244a4a355
13c34c601c03
146414d99877
1535ade9c86b
hex1e4556c171

130012332401 has 4 divisors (see below), whose sum is σ = 148585522752. Its totient is φ = 111439142052.

The previous prime is 130012332383. The next prime is 130012332407. The reversal of 130012332401 is 104233210031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 130012332401 - 26 = 130012332337 is a prime.

It is a super-2 number, since 2×1300123324012 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130012332407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9286595165 + ... + 9286595178.

It is an arithmetic number, because the mean of its divisors is an integer number (37146380688).

Almost surely, 2130012332401 is an apocalyptic number.

It is an amenable number.

130012332401 is a deficient number, since it is larger than the sum of its proper divisors (18573190351).

130012332401 is an equidigital number, since it uses as much as digits as its factorization.

130012332401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18573190350.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 130012332401 its reverse (104233210031), we get a palindrome (234245542432).

The spelling of 130012332401 in words is "one hundred thirty billion, twelve million, three hundred thirty-two thousand, four hundred one".

Divisors: 1 7 18573190343 130012332401