Base | Representation |
---|---|
bin | 11000001101110111… |
… | …10101101010100001 |
3 | 1020120002011000011221 |
4 | 30012323311222201 |
5 | 203111310021424 |
6 | 5550033535041 |
7 | 640116546202 |
oct | 140673655241 |
9 | 36502130157 |
10 | 13001251489 |
11 | 557195a746 |
12 | 262a114481 |
13 | 12c271c525 |
14 | 8b49b35a9 |
15 | 5115ec9e4 |
hex | 306ef5aa1 |
13001251489 has 2 divisors, whose sum is σ = 13001251490. Its totient is φ = 13001251488.
The previous prime is 13001251481. The next prime is 13001251553. The reversal of 13001251489 is 98415210031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12903142464 + 98109025 = 113592^2 + 9905^2 .
It is an emirp because it is prime and its reverse (98415210031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13001251489 - 23 = 13001251481 is a prime.
It is not a weakly prime, because it can be changed into another prime (13001251481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500625744 + 6500625745.
It is an arithmetic number, because the mean of its divisors is an integer number (6500625745).
Almost surely, 213001251489 is an apocalyptic number.
It is an amenable number.
13001251489 is a deficient number, since it is larger than the sum of its proper divisors (1).
13001251489 is an equidigital number, since it uses as much as digits as its factorization.
13001251489 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 34.
The spelling of 13001251489 in words is "thirteen billion, one million, two hundred fifty-one thousand, four hundred eighty-nine".
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