Base | Representation |
---|---|
bin | 11101100011111100000100… |
… | …000000010100101110111010 |
3 | 122001100010100001121011000000 |
4 | 131203330010000110232322 |
5 | 114020113132141223002 |
6 | 1140303054033053430 |
7 | 36246062614524300 |
oct | 3543740400245672 |
9 | 561303301534000 |
10 | 130013022211002 |
11 | 38476238673087 |
12 | 126b948a0b7276 |
13 | 5771238432798 |
14 | 241694186a270 |
15 | 1006e0c93661c |
hex | 763f04014bba |
130013022211002 has 84 divisors (see below), whose sum is σ = 340133589536346. Its totient is φ = 37146577754160.
The previous prime is 130013022210983. The next prime is 130013022211019. The reversal of 130013022211002 is 200112220310031.
130013022211002 is a `hidden beast` number, since 1 + 300 + 1 + 30 + 222 + 110 + 0 + 2 = 666.
It can be written as a sum of positive squares in only one way, i.e., 128257187854761 + 1755834356241 = 11325069^2 + 1325079^2 .
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 41 ways as a sum of consecutive naturals, for example, 909848649 + ... + 909991532.
Almost surely, 2130013022211002 is an apocalyptic number.
130013022211002 is an abundant number, since it is smaller than the sum of its proper divisors (210120567325344).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130013022211002 is an equidigital number, since it uses as much as digits as its factorization.
130013022211002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1819840215 (or 1819840193 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 130013022211002 its reverse (200112220310031), we get a palindrome (330125242521033).
The spelling of 130013022211002 in words is "one hundred thirty trillion, thirteen billion, twenty-two million, two hundred eleven thousand, two".
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