Base | Representation |
---|---|
bin | 1011110100110001101000… |
… | …1111000100001001100100 |
3 | 1201000220122101021102101010 |
4 | 2331030122033010021210 |
5 | 3201003133334134024 |
6 | 43352415000102220 |
7 | 2511212325654234 |
oct | 275143217041144 |
9 | 51026571242333 |
10 | 13001306161764 |
11 | 4162906426428 |
12 | 155b8a7164970 |
13 | 73403046cbbb |
14 | 32d3a36abcc4 |
15 | 1782d9192b29 |
hex | bd31a3c4264 |
13001306161764 has 24 divisors (see below), whose sum is σ = 30336472031488. Its totient is φ = 4333755722400.
The previous prime is 13001306161763. The next prime is 13001306161769. The reversal of 13001306161764 is 46716160310031.
It is a super-3 number, since 3×130013061617643 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (13001306161763) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3090189 + ... + 5962539.
Almost surely, 213001306161764 is an apocalyptic number.
It is an amenable number.
13001306161764 is an abundant number, since it is smaller than the sum of its proper divisors (17335165869724).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13001306161764 is a wasteful number, since it uses less digits than its factorization.
13001306161764 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3249555 (or 3249553 counting only the distinct ones).
The product of its (nonzero) digits is 54432, while the sum is 39.
Adding to 13001306161764 its reverse (46716160310031), we get a palindrome (59717466471795).
The spelling of 13001306161764 in words is "thirteen trillion, one billion, three hundred six million, one hundred sixty-one thousand, seven hundred sixty-four".
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