13001310011113 has 2 divisors, whose sum is σ = 13001310011114. Its totient is φ = 13001310011112.

The previous prime is 13001310011047. The next prime is 13001310011177. The reversal of 13001310011113 is 31111001310031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12437133263424 + 564176747689 = 3526632^2 + 751117^2 .

It is an emirp because it is prime and its reverse (31111001310031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13001310011113 - 2²⁵ = 13001276456681 is a prime.

It is not a weakly prime, because it can be changed into another prime (13001310011713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500655005556 + 6500655005557.

It is an arithmetic number, because the mean of its divisors is an integer number (6500655005557).

Almost surely, 2^{13001310011113} is an apocalyptic number.

It is an amenable number.

13001310011113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001310011113 is an equidigital number, since it uses as much as digits as its factorization.

13001310011113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27, while the sum is 16.

Adding to 13001310011113 its reverse (31111001310031), we get a palindrome (44112311321144).

The spelling of 13001310011113 in words is "thirteen trillion, one billion, three hundred ten million, eleven thousand, one hundred thirteen".