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13001311102033 is a prime number
BaseRepresentation
bin1011110100110001101010…
…0001111010010001010001
31201000220122201120102011001
42331030122201322101101
53201003141120231113
643352415254022001
72511212415651322
oct275143241722121
951026581512131
1013001311102033
1141629091a00a1
12155b8a8947901
137340314ac737
1432d3a41d6449
151782d981b7dd
hexbd31a87a451

13001311102033 has 2 divisors, whose sum is σ = 13001311102034. Its totient is φ = 13001311102032.

The previous prime is 13001311102027. The next prime is 13001311102057. The reversal of 13001311102033 is 33020111310031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8770790248704 + 4230520853329 = 2961552^2 + 2056823^2 .

It is a cyclic number.

It is not a de Polignac number, because 13001311102033 - 241 = 10802287846481 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13001311102033.

It is not a weakly prime, because it can be changed into another prime (13001311162033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500655551016 + 6500655551017.

It is an arithmetic number, because the mean of its divisors is an integer number (6500655551017).

Almost surely, 213001311102033 is an apocalyptic number.

It is an amenable number.

13001311102033 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001311102033 is an equidigital number, since it uses as much as digits as its factorization.

13001311102033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13001311102033 its reverse (33020111310031), we get a palindrome (46021422412064).

The spelling of 13001311102033 in words is "thirteen trillion, one billion, three hundred eleven million, one hundred two thousand, thirty-three".